SOLUTION: The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?
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Question 305978: The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
P=2L+2W
L=2W+2
244=2(2W+2)+2W
244=4W+4+2W
244=6W+4
6W=244-4
6W=240
W=240/6
W=40 ANS. FOR THE WIDTH.
L=2*40+2=80+2=82 ANS. FOR THE LENGTH.
PROOF:
244=2*82+2*40
244=164+80
244=244
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