SOLUTION: Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 36 meters and the length is 4 meters more than the width.
36= l(w+4)
how would i get act
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Question 297894: Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 36 meters and the length is 4 meters more than the width.
36= l(w+4)
how would i get actual numbers out of this???
Found 2 solutions by checkley77, JBarnum:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
36= l(w+4) Wrong equation
--------------------------
L=W+4
36=2L+2W iS THE PERIMETER FORMULA.
36=2(W+4)+2W
36=2W+8+2W
36=4W+8
4W=36-8
4W=28
W=28/4
W=7 ans. for the width.
L=7+4=11 ans. for the length.
Proof:
36=2*11+2*7
36=22+14
36=36
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
almost but need to reread the question
know your formulas
"The perimeter is 36 meters"
"the length is 4 meters more than the width"
______________
solve
find length
_____________________
Check
correct
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