SOLUTION: Samuel left the house at noon heading to David's store, 60 miles away. David left his store at 2 pm, heading to Samuel's house and traveling at twice Samuel's speed. The two men me

Question 296126: Samuel left the house at noon heading to David's store, 60 miles away. David left his store at 2 pm, heading to Samuel's house and traveling at twice Samuel's speed. The two men met at 3 p.m. How fast was David traveling?
Found 2 solutions by kitkat231, MathTherapy:
Answer by kitkat231(1) (Show Source): You can put this solution on YOUR website!
davids speed would have been three times slower then samuels if they both got there at 3 pm
Answer by MathTherapy(10553) (Show Source): You can put this solution on YOUR website!
Samuel left the house at noon heading to David's store, 60 miles away. David left his store at 2 pm, heading to Samuel's house and traveling at twice Samuel's speed. The two men met at 3 p.m. How fast was David traveling?

Since the journey from David's store to Samuel's house is 60 miles, then the sum of the distances traveled by the 2 will total 60, or,

Samuel's distance covered + David's distance covered = 60 miles

Let Samuel's speed be S, then David's speed will be 2S, since David is traveling at twice Samuel's speed

Then Samuel's distance traveled = S(3), since it took him 3 hours to cover the distance to the meeting point, and

David's distance covered = 2S(1), since it took David 1 hour to cover the distance to the meeting point

Therefore, we'll have: 3S + 2S = 60

5S = 60

S =

Now, since S, or Samuel's speed is 12 mph, then David's speed = mph (2S, or 2*12).
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