# SOLUTION: COMPARING AREAS A WIRE 390 IN. LONG IS CUT INTO TWO PIECES. ONE PIECE IS FORMED INTO A SQUARE. THE OTHER PIECE IS FORMED INTO A CIRCLE. IF THE TWO FIGURES HAVE THE SAME AREA, WHAT

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: COMPARING AREAS A WIRE 390 IN. LONG IS CUT INTO TWO PIECES. ONE PIECE IS FORMED INTO A SQUARE. THE OTHER PIECE IS FORMED INTO A CIRCLE. IF THE TWO FIGURES HAVE THE SAME AREA, WHAT      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Geometry Solvers Lessons Answers archive Quiz In Depth

 Question 287667: COMPARING AREAS A WIRE 390 IN. LONG IS CUT INTO TWO PIECES. ONE PIECE IS FORMED INTO A SQUARE. THE OTHER PIECE IS FORMED INTO A CIRCLE. IF THE TWO FIGURES HAVE THE SAME AREA, WHAT ARE THE LENGTHS OF THE TWO PIECES OF WIRE (TO THE NEAREST TENTH OF AN IN.) THANKS. Answer by CharlesG2(828)   (Show Source): You can put this solution on YOUR website!COMPARING AREAS A WIRE 390 IN. LONG IS CUT INTO TWO PIECES. ONE PIECE IS FORMED INTO A SQUARE. THE OTHER PIECE IS FORMED INTO A CIRCLE. IF THE TWO FIGURES HAVE THE SAME AREA, WHAT ARE THE LENGTHS OF THE TWO PIECES OF WIRE (TO THE NEAREST TENTH OF AN IN.) THANKS. will do this , but please in future avoid capital letters, okay? it's like shouting area square = side^2 area circle = pi*r^2 (r being radius) if areas equal then side = r*sqrt(pi) perimeter square = 4 * side = 4*r*sqrt(pi) perimeter circle = 2*r*pi 390 = 4*r*sqrt(pi) + 2*r*pi (and then need to solve for r) 390 = r * (4*sqrt(pi) + 2*pi) 390 = r * (7.08981540362206410919266993336458 + 6.28318530717958647692528676655901) 390 = r * (13.3730007108016505861179566999236) 29.1632378128110690359981779219183 = r (now calculate perimeters) perimeter square = 206.761972664761351531516548842056 perimeter circle = 183.238027335238648468483451157944 perimeter square approx. 206.8 inches perimeter circle approx. 183.2 inches