SOLUTION: The length of a photograph is 1 cm less than twice the width. The area is 45cm squared. Find the dimensions of the photograph. the problem must be solved algebracly using the q

Question 281243: The length of a photograph is 1 cm less than twice the width. The area is 45cm squared. Find the dimensions of the photograph.
the problem must be solved algebracly using the quadratic formula, factoring or anything like that. thanks
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Let width be w and length be l.

so either w-5 =0 or 2w+9=o
w = 5 or w = -9/2
since a distance can't be nagative, width = 5
so length = 2*5-1 = 9
Does 9*5 = 45??
RELATED QUESTIONS
The length of a photograph is 1cm less than twice the width. The area is 23cm squared.... (answered by checkley71)

The length of a rectangle is 1 cm less than twice the width. The area is 45cm^2. what are (answered by josgarithmetic,MathTherapy)

a rectangular photograph has an area of 40 inches. If the width of the photograph is 3... (answered by ikleyn)

The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle (answered by ewatrrr)

this problem starts the length of a rectangle is 5 cm less than twice the width. the... (answered by checkley71)

A rectangular photograph is twice as long as it is wide. The perimeter of the photograph (answered by algebrahouse.com)

A rectangle has an area of 36 cm^2. The length is 1 cm less than twice the width. Find... (answered by TimothyLamb)

THe perimeter of a rectangular photograph is 22 inches. The length of the photograph is 1 (answered by swincher4391)

The length of a rectangle is 5 cm greater than twice the width. The area is 33 cm... (answered by 428225)