SOLUTION: find the equation of the straight line joining A=(4,-2) c=(3,0)show working.

Question 27478: find the equation of the straight line joining A=(4,-2) c=(3,0)show working.

Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
find the equation of the straight line joining A=(4,-2) c=(3,0)show working.
The formula for the equation to the stline joining two given pts
The equation of the straight line joining two given points A(x1,y1) and B(x2,y2) is given by
(y- y1)/(y1- y2) = (x- x1)/(x1- x2)
Applying the above formula to the stline joining A(4,-2) and C(3,0)
we have (y-(-2))/[(-2)-0] = (x-4)/(4-3) (where x1=4, y1=-2 and x2=3, y1=0)
That is (y+2)/(-2) = (x-4)/1
That is (y+2) X 1 = (-2) X (x-4) (cross multiplication)
(y+2) = -2x +8
That is 2x +y +2-8 = 0 (Transposing, change side than change sign)
2x+ y -6 = 0
Answer: The required line is 2x + y - 6 = 0
Verification:
Testing for A(4,-2) in the answer, (putting x=4, y=-2)
LHS = 2X4 -2 -6 = 8-8 =0 =RHS
Testing for C(3,0) in the answer, (putting x=3, y=0)
LHS = 2X3 +0 -6 = 6-6 =0 =RHS
Therefore both the given points satisfy the equation that we have got. Hence we are right.
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