SOLUTION: (t+k)/2=(t^2-t-7)/(2+2t) solve for t.

Question 257092: (t+k)/2=(t^2-t-7)/(2+2t)
solve for t.
Found 2 solutions by stanbon, drk:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(t+k)/2=(t^2-t-7)/(2+2t)
solve for t.
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Multiply both sides by 2 to get:
(t+k) = (t^2-t-7)/(1+t)
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Multiply both sides by 1+t to get:
t + t^2 + k + kt = t^2-t-7
2t+kt = -(k+7)
t(2+k) = -(k+7)
t = -(k+7)/(k+2)
======================
Cheers,
Stan H.

Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
We have the following:
=
step 1 - cross multiply to get

step 2 - distribute to get

simplify and get

pulling out the GCF of t, we get

dividing, we get

simplifying, we get

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