SOLUTION: Packaging computers The phillips paper company makes rectangular peices of cardboard for packing computers. The sheets of cardboard are to have and area of 99 square inches and t

Question 238879: Packaging computers
The phillips paper company makes rectangular peices of cardboard for packing computers. The sheets of cardboard are to have and area of 99 square inches and the length of a sheet is to be 5 inches more than 2/3 its width. Determine the length and width of the cardboard to be manufactured.
I have tried 99=(2/3w^2 +5)(w) since Area= L X W so i get 99= 2/3w^2 +5w then i set it to 0 and i try to factor over and over again im just getting no wou
sihere please help!
thank you
sincerly me
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The Phillips paper company makes rectangular pieces of cardboard for packing computers.
The sheets of cardboard are to have and area of 99 square inches and the length of a sheet is to be 5 inches more than 2/3 its width.
Determine the length and width of the cardboard to be manufactured.
I have tried 99=(2/3w^2 +5)(w) since Area= L X W so i get 99= 2/3w^2 +5w then i set it to 0
:
I think you are on the right track here, we have
w^2 + 5w - 99 = 0
:
Get rid of this annoying fraction, multiply each term by 3, results
2w^2 + 15w - 297 = 0
:
Actually this will factor, with a little persistence we come up with
(2w + 33)(w - 9) = 0
:
Positive solution is; (we don't care about the neg solution):
w = 9 is the width
:
Find the length
L = (9) + 5
L = 6 + 5
L = 11 is the length (which would give you an area of 99)
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