# SOLUTION: A tree (altitude =a) breaks somewhere in its height and falls over. The tip of the tree touches ground at 20' from stump (base b= 20') The created hypotonuse (c) is equal to 2 t

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 Question 23073: A tree (altitude =a) breaks somewhere in its height and falls over. The tip of the tree touches ground at 20' from stump (base b= 20') The created hypotonuse (c) is equal to 2 times a. What was the height of the tree before the tree broke and fell? given that: a^2 + b^2 = c^2 I end up with x^2 + 20^2 = 2x^2 Now where do I go to finish? (Next: x^2 - 2x^2 = 400)? I can't remember how to solve this. My book has no literal explanation of the steps (I'm too dumb to derive the solution)Answer by stanbon!(97)   (Show Source): You can put this solution on YOUR website!How can a tree that is "a" high have a fallen part that is "2a" in length? Please check the statement of your problem. Cheers, Stan H.