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The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width by 10 inches, what is the screen length and width?
Step 1. Perimeter P means adding up all 4 sides of a rectangle.
Step 2. Let w be the width.
Step 3. Let 2w+10 be the length since the length exceeds twice its width by 10 inches
Step 4. Then, P=w+w+2w+10+2w+10=6w+20=272
Step 5. Solving yields the following steps:
Subtract 20 from both sides of the equation
Divide by 6 to both sides of the equation
. Then P=2(42+94)=272 which is a true statement.
Step 6. ANSWER: The width is 42 inches and the length is 94 inches.
I hope the above steps were helpful.
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