SOLUTION: The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width 10 inches, what is the screen length and width?

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 Question 228526: The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width 10 inches, what is the screen length and width?Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width by 10 inches, what is the screen length and width? Step 1. Perimeter P means adding up all 4 sides of a rectangle. Step 2. Let w be the width. Step 3. Let 2w+10 be the length since the length exceeds twice its width by 10 inches Step 4. Then, P=w+w+2w+10+2w+10=6w+20=272 Step 5. Solving yields the following steps: Subtract 20 from both sides of the equation Divide by 6 to both sides of the equation and . Then P=2(42+94)=272 which is a true statement. Step 6. ANSWER: The width is 42 inches and the length is 94 inches. I hope the above steps were helpful. For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry. Good luck in your studies! Respectfully, Dr J