SOLUTION: The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width 10 inches, what is the screen length and width?

Question 228526: The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width 10 inches, what is the screen length and width?
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangular screen is 272 inches. If the length of the screen exceeds twice its width by 10 inches, what is the screen length and width?

Step 1. Perimeter P means adding up all 4 sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let 2w+10 be the length since the length exceeds twice its width by 10 inches

Step 4. Then, P=w+w+2w+10+2w+10=6w+20=272

Step 5. Solving yields the following steps:

Subtract 20 from both sides of the equation

Divide by 6 to both sides of the equation

and . Then P=2(42+94)=272 which is a true statement.

Step 6. ANSWER: The width is 42 inches and the length is 94 inches.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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