SOLUTION: The area of a circle 8 inches in diameter is greater than the combined areas of a circle 6 inches in diameter and a circle 2 inches in diameter by approximately how many square inc
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Question 226384: The area of a circle 8 inches in diameter is greater than the combined areas of a circle 6 inches in diameter and a circle 2 inches in diameter by approximately how many square inches?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
area of a circle is equal to
r equals diameter / 2
Circle 1 has a radius of 8/2 = 4 inches.
Circle 2 has a radius of 6/2 = 3 inches.
Circle 3 has a radius of 2/2 = 1 inch.
Area of circle 1 equals = 16*
Area of circle 2 equals = 9*
Area of circle 3 equals = 1*
Differences in the areas is (16-9-1)* equals 6* equals 18.84955592 square inches.
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