SOLUTION: Can you please explain how I can solve this problem? The legnth of a rectangle is 5ft more than its width. If the perimeter is 70ft, find the dimension.

Question 215723: Can you please explain how I can solve this problem?
The legnth of a rectangle is 5ft more than its width. If the perimeter is 70ft, find the dimension.
Found 2 solutions by rfer, drj:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
P=2w+2l
70=2w+2(w+5)
70=2w+2w+10
60=4w
15=w
w=15
l=w+5=20
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!

The length of a rectangle is 5ft more than its width. If the perimeter is 70ft, find the dimension.

Step 1. Let w be the width and w+5 be the length.

Step 2. Perimeter P means that we add up all the lengths of the four sides.

Step 3. Then we have

Subtract 10 from both sides of the equation

Divide 4 to both sides of the equation

With w=15, then w+5=20. Check perimeter...P=15+15+20+20=70 which is a true statement.

Step 4. ANSWER. The width is 15 ft and the length is 20 ft.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
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