SOLUTION: If one side of a square is increased by 8cm and an adjacent side decreased by 2cm, a rectangle is formed whose perimeter is 40cm. Find the length of a side of the square.

Question 214172: If one side of a square is increased by 8cm and an adjacent side decreased by 2cm, a rectangle is formed whose perimeter is 40cm. Find the length of a side of the square.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the length of a side of the square = s, then the perimeter is expressed by:
Increase one side by 8cm. to get (s+8)cm. and decrease an adjacent side by 2cm. to get (s-2)cm.. The resulting perimeter (P) is 40cm.
Divide both sides by 2.
Simplify.
Subtract 6 from both sdes.
Divide both sides by 2.

The length of a side of the square is 7cm.

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