SOLUTION: A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the len
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Question 211581: A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?
Thx
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Recall that the perimeter of any triangle is
P = length of side1 + length of side2 + length of side3
Now let
x = length of side1
y = length of side2
z = length of side3
So the perimeter is now . Because the triangle is an isosceles, there are two sides that are equal. So let's make which will make the base be 'x'. Since the "triangle has a base that is 2 inches shorter than either of the equal sides", this means or
Start with the given equation.
Plug in (the given perimeter), , and
Combine like terms.
Add to both sides.
Combine like terms.
Divide both sides by to isolate .
Reduce.
Rearrange the equation.
Since , we know that also. So the length of the equal sides is 15 inches. Subtract 2 from this to get 13
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Answer:
So the triangle has side lengths of 13, 15, and 15 inches
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