SOLUTION: Three times the number of reds is one less than twice the number of blues. If the sum of the reds and the blues is 13, how many are red and how many are blue?

Question 209367This question is from textbook
: Three times the number of reds is one less than twice the number of blues. If the sum of the reds and the blues is 13, how many are red and how many are blue? This question is from textbook

Found 2 solutions by Earlsdon, checkley77:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let R = the number of reds and B = the number of blues.
3R = 2B-1 and...
R+B = 13 Rewrite as:
R = 13-B and substitute into the first equation.
3(13-B) = 2B-1 Simplify.
39-3B = 2B-1 Add 3B to both sides.
39 = 5B-1 Add 1 to both sides.
40 = 5B Divide both sides by 5.
8 = B and R = 13-8 = 5.
There are 5 red and 8 blue.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
3R=2B-1
R+B=13 or R=13-B
3(13-B)=2B-1
39-3B=2B-1
-3B-2B=-1-39
-5B=-40
B=-40/-5
B=8 BLUES.
3R=2*8-1
3R=16-1
3R=15
R=15/3
R=5 REDS.
PROOF:
5+8=13
13=13

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