# SOLUTION: The dimensions of a garden are in whole numbers. If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. What were the dimensions and area of t

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The dimensions of a garden are in whole numbers. If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. What were the dimensions and area of t      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Geometry Solvers Lessons Answers archive Quiz In Depth

 Question 206365: The dimensions of a garden are in whole numbers. If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. What were the dimensions and area of the original rectangle. I know the answer but cannot find the math to get to it!Answer by ankor@dixie-net.com(15652)   (Show Source): You can put this solution on YOUR website!The dimensions of a garden are in whole numbers. If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. What were the dimensions and area of the original rectangle. : Let L = original length Let W = original width LW = original area : (L-3) = new length (W-1) = new width New area = (L-3)*(W-1) = (LW - L - 3W + 3) : Original area = twice new area LW = 2(LW - L - 3W + 3) : LW = 2LW - 2L - 6W + 6 : 2LW - LW - 2L - 6W + 6 = 0 : LW - 2L = 6W - 6 : L(W - 2) = 6W - 6 L = Find a value for W that produces an integer value for L W = 3 L = L = 12 : original: 12 by 3 original area = 36 : Check solution New area: 9 * 2 = 18, half the original