SOLUTION: Please help with me find an equation of line l and solve for y when Line l goes through (0,0) and is perpendicular to the line through (0,6) and (-5,0). I am stumped because I don

Question 205194: Please help with me find an equation of line l and solve for y when Line l goes through (0,0) and is perpendicular to the line through (0,6) and (-5,0). I am stumped because I don't think there is a slope for the first line. Any help is greatly appreciated.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(0,6)(-5,0)
The equation for this line is:
Y=mX+b
m=slope=(y2-y1)/(x2-x1)=(0-6)/(-5-0)=-6/-5=6/5 ans.
6=6/5*0+b
6=b ans. for the y intercept.
y=6x/5+6 is the equation for this line. (red line)
A perpendicular line will have a slope=-5/6 passing through (0,0).
0=-5/6*0+b
0=b ans. for the y intercept for this line.
y=-5x/6+0s the equation for thjis line. (green line)
(graph 300x300 pixels, x from -6 to 6, y from -6 to 6, of TWO functions 6x/5 +6 and y = -5x/6).

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