SOLUTION: The Great Pyramid of Cheops has a square base of 771 ft on a side and a height of 486 ft. How many apartments 35 ft x 20 ft x 8 ft would be needed to have a volume equivalent to

Question 193536This question is from textbook
: The Great Pyramid of Cheops has a square base of 771 ft on
a side and a height of 486 ft. How many apartments 35 ft x
20 ft x 8 ft would be needed to have a volume equivalent to
that of the Great Pyramid’s?
Please show me how to work this problem. Thank you.This question is from textbook

Found 2 solutions by vleith, RAY100:
Answer by vleith(2517) (Show Source):
You can put this solution on YOUR website!
First find the volume in a square pyramid.
http://www.mathsteacher.com.au/year10/ch14_measurement/25_pyramid/21pyramid.htm

cubic feet
Next find the volume in one cube shaped apartment

cubic feet
Now see how times larger in volume the pyramid is compared to the apartment

So the volume of 17183 complete apartments fits in there.

Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website!
Volume of pyramid =(1/3)*Base*Height=(1/3)(771^2)(486)=96,299,442
Volume of rect solid is l*w*h=35*20*8=5600
ratio is 96,299,442/5600=17,196.3