SOLUTION: The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width? THANK YOU TO WHO EVER HELPS ME WITH THIS. THANK YOU THANK YOU THANK YOU.

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Question 191931: The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width? THANK YOU TO WHO EVER HELPS ME WITH THIS. THANK YOU THANK YOU THANK YOU.
Found 2 solutions by nerdybill, Earlsdon:
Answer by nerdybill(5411) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width
.
Let w = width
then
4w = length
.
w(4w) = 64
4w^2 =64
w^2 = 16
w = 4 cm (width)
.
Length:
4w = 4(4) = 16 cm (length)

Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the formula for the area of a rectangle:
A+=+L%2AW
Now since you are given that the length (L) is four times the width (W), and that the area (A) is 64 sq.cm., you can substitute A+=+64 and L+=+4W in the formula for the area:
64+=+%284W%29W Simplifying this, we get:
64+=+4W%5E2 Divide both sides by 4.
16+=+W%5E2 Take the square root of both sides.
4+=+W N.B. We use only the positive solution of the square root because the width (W) is a positive quantity.
So the width is 4 cm. and the length L = 4W, so:
L+=+16
The length is 16 cm.