SOLUTION: The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width? THANK YOU TO WHO EVER HELPS ME WITH THIS. THANK YOU THANK YOU THANK YOU.

Question 191931: The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width? THANK YOU TO WHO EVER HELPS ME WITH THIS. THANK YOU THANK YOU THANK YOU.
Found 2 solutions by nerdybill, Earlsdon:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width
.
Let w = width
then
4w = length
.
w(4w) = 64
4w^2 =64
w^2 = 16
w = 4 cm (width)
.
Length:
4w = 4(4) = 16 cm (length)

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Start with the formula for the area of a rectangle:

Now since you are given that the length (L) is four times the width (W), and that the area (A) is 64 sq.cm., you can substitute and in the formula for the area:
Simplifying this, we get:
Divide both sides by 4.
Take the square root of both sides.
N.B. We use only the positive solution of the square root because the width (W) is a positive quantity.
So the width is 4 cm. and the length L = 4W, so:

The length is 16 cm.
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