SOLUTION: I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double

Question 185188: I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previous sector 6 times, find the value of the angle at the middle of the inital sector. PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPP''
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
first sector is x
second is 2x
third is 4x
fourth is 8x
fifth is 16x
sixth is 32x
last is 64x
So you have
(x + 2x + 4x + 8x + 16x + 32x + 64x) = 127x
there are 360degrees in a circle. So the angle x is 360/127
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