SOLUTION: the width of a rectangle is 3 inches less than twice its lenght. If perimeter of the rectangle is 36 inches, find its lenght and width.

Algebra.Com
Question 183497: the width of a rectangle is 3 inches less than twice its lenght. If
perimeter of the rectangle is 36 inches, find its lenght and width.

Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
W=L-3
2W+2L=36
2(L-3)+2L=36
2L-6+2L=36
4L=36+6
4L=42
L=42/4
L=10.5 IN.
W=10.5-3=7.5 IN.
PROOF:
2*7.5+2*10.5=36
15+21=36
36=36

RELATED QUESTIONS

thw width of a rectngle is 2 inches less than its lenght. If the perimeter is 36 inches.... (answered by nyc_function)
the width of a rectangle is 10 inches less than its length. If the perimeter of the... (answered by josgarithmetic)
The length of a rectangle is five inches less than twice its width. If the rectangle has... (answered by Alan3354)
the length of a rectangle is 3 less than than twice its width the perimeter of the... (answered by stanbon)
The width of a rectangle is 9 inches less than its lenght. If the area of the rectangle... (answered by mananth)
if the perimeter of a rectangle is 108 inches, and its lenght is 3 1/4 feet, find it... (answered by tutorcecilia)
with of a rectangle is 3 inches less than one-half the lenght. what the lenght and width... (answered by checkley71,doukungfoo,edjones)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the (answered by Paul)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the (answered by fractalier,Earlsdon)