SOLUTION: The perimeter of a rectangle is 32 inches and the area is 60 square inches. Find the length and width of the rectangle.
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Question 181547This question is from textbook
: The perimeter of a rectangle is 32 inches and the area is 60 square inches. Find the length and width of the rectangle.
This question is from textbook
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 32 inches and the area is 60 square inches. Find the length and width of the rectangle.
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Area = l*w = 60
Perimeter = 2l + 2w = 32 --> l+w = 16
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l*w = 60
Sub for w, w = 16-l
l*(16-l) = 60
l^2 - 16l + 60 = 0
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(l-6)*(l-10) = 0
l = 10, l = 6
So it's l = 10, w = 6 or vice versa
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