SOLUTION: The perimeter of a rectangular yard is 290 feet. If its length is 25 feet greater than its width, what are the dimensions of the yard. Use the five step method to solve.

Question 177577: The perimeter of a rectangular yard is 290 feet. If its length is 25 feet greater than its width, what are the dimensions of the yard. Use the five step method to solve.
Found 2 solutions by Mathtut, checkley75:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
again I will leave the 5-steps to you
:
P=2L+2W...eq 1
:
L=W+25....eq 2
:
P=290.....eq 3
:
take values of eq 2 and 3 and plug them into eq 1
:
290=2(W+25)+2W
:
290=2W+50+2W......distributed right side
:
240=4W
:
feet
:
feet
:
Yard is 60x85
:

Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
2L+2W=290
L=W+25
2(W+25)+2W=290
2W+50+2W=290
4W=290-50
4W=240
W=240/4
W=60 ans.
L=60+25=85 ans.
Proof:
2*85+2*60=290
160+120=290
290=290

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