SOLUTION: a ladder is 25ft long. the ladder needs to reach to a window that is 24ft above the ground.how far awayfrom the building should the bottom of the ladder be placed?

Question 172988This question is from textbook algebra 1
: a ladder is 25ft long. the ladder needs to reach to a window that is 24ft above the ground.how far awayfrom the building should the bottom of the ladder be placed? This question is from textbook algebra 1

Found 3 solutions by jim_thompson5910, Mathtut, monika_p:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let x=the distance from the bottom of the ladder to the building.

We basically have this triangle set up:

Since the legs are and this means that and

Also, since the hypotenuse is , this means that .

Start with the Pythagorean theorem.

Plug in , ,

Square to get .

Square to get .

Subtract from both sides.

Combine like terms.

Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).

Simplify the square root.

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Answer:

So the solution is .

This means that the bottom of the ladder should be placed 7 ft from the building.

Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!
pathagorean theorem:
:

:

:

:
feet
x=-7 was thrown out because you cant have negative length
Answer by monika_p(71)   (Show Source): You can put this solution on YOUR website!
The ladder will make a right triangle with wall of the building and ground. The right angle will be between wall and ground and ladder will be hypotenuse of the triangle.Lets ladder will have lenght x=25, wall y=24 and distance on the ground z, which we have to find. To find lenght z use Pythagorean Theorem
y^2+z^2=x^2
24^2+z^2=25^2
z^2= 625-576
z^2=49
z=7
Answer: The bottom of the ladder should be placed 7ft away from building
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