SOLUTION: The area of a right triangle is 250in square. Find the lengths of its legs if one leg is 5inches longer than the other.

Question 171182: The area of a right triangle is 250in square. Find the lengths of its legs if one leg is 5inches longer than the other.
Found 2 solutions by oscargut, monika_p:
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
legs are x and x+5
area = x(x+5)/2=250
x(x+5)=500
x^2+5x-500=0
=

x=20 or x= -25 but x must be > 0 so solution is x=20
Answer: lengths of legs are 20 and 25 inches
Answer by monika_p(71) (Show Source): You can put this solution on YOUR website!
The formula for the area of a triangle (abc)is:
, where b is the base of a triangle and h is the height
The base and height of a triangle must be perpendicular to each other, then in a right triangle height is equal to the leg of the triangle, in this case a=h
you have given A= 250, h=5

Substitute and simplify:

then:
b = 100
Answer: the lenght of second leg of the right triangle is 100 in

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