SOLUTION: American flag has a perimeter of 28 feet. Find the dimensions of the flag if the length is 4 feet less than twice it's width
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Question 167365This question is from textbook Elemtary Alebgra for College Students
: American flag has a perimeter of 28 feet. Find the dimensions of the flag if the length is 4 feet less than twice it's width
This question is from textbook Elemtary Alebgra for College Students
Found 2 solutions by Mathtut, aswathytony:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
P=2w+2l eq 1
l=2w-4 eq 2
:
substitute P=28 and l's value in eq 2 into eq 1--->28=2w+2(2w-4)
:
28=2w+4w-8---- so
Answer by aswathytony(47) (Show Source): You can put this solution on YOUR website!
let 'l' be the length and 'w' be the width of the flag.
then perimeter = 2l +2w ( rectangle)
given, perimeter = 28 ft
i.e. 2l +2w = 28 ft
2 (l +w) = 28
l + w = 28 /2 = 14 ..........(1)
given length is 4 ft less than its width
i.e . l = w - 4 ...........(2)
from (1) & (2)
w - 4 + w = 14
2w - 4 = 14
2w = 14+4
2w = 18
w = 18 /2 = 9ft
l = w - 4 = 9 - 4 = 5 ft
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