SOLUTION: The width of a certain rectangle exceeds twice its length by three inches, and four times its lenght is twelve less than its perimeter. Find the dimensions of the rectangle. thi

You can put this solution on YOUR website!
You're getting there but you only used half of the information.
"four times its lenght is twelve less than its perimeter"


Now you have another equation for P.
Put that together with your other equation for P.

Equate them and solve for L.

Re-post a question if you get stuck.