# SOLUTION: The perimeter of a rectangular room is 37 3/5 ft. The width is 6 4/5 feet. Find the length. I know the formula is p=2l + 2w but the fractions and information are confusing

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The perimeter of a rectangular room is 37 3/5 ft. The width is 6 4/5 feet. Find the length. I know the formula is p=2l + 2w but the fractions and information are confusing      Log On

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 Click here to see ALL problems on Geometry Word Problems Question 160850: The perimeter of a rectangular room is 37 3/5 ft. The width is 6 4/5 feet. Find the length. I know the formula is p=2l + 2w but the fractions and information are confusingAnswer by gonzo(654)   (Show Source): You can put this solution on YOUR website!P = 2*L + 2*W 37+(3/5) = 2*L + 2*(6+(4/5)) making the improper fraction into proper fraction gets 188/5 = 2*L + (2*(34/5)) this becomes 188/5 = 2*L + (2*34)/5 multiplying both sides of the equation by 5 to remove the denominators and the equation becomes 188 = 2*5*L + (2*34) which becomes 188 = 10*L + 68 subtracting 68 from both sides and equation becomes 188-68 = 10*L which becomes 120 = 10*L which becomes L = 12 ----- substituting in the original equation gets 37 + (3/5) = (2*12) + 2*(6 + 4/5) converting to proper fraction and equation becomes 188/5 = 2*12 + 2*(34/5) multiplying both sides by 5 to remove the denominators and equation becomes 188 = 2*5*12 + 2*34 which becomes 188 = 120 + 68 which becomes 188 = 188 so answer is good.