SOLUTION: Find the angles of a triangle where one angle is three times a second angle and six times the third angle. I think the variables should be: x = one angle 3x = second angle 6x =

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Find the angles of a triangle where one angle is three times a second angle and six times the third angle. I think the variables should be: x = one angle 3x = second angle 6x =      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 160779: Find the angles of a triangle where one angle is three times a second angle and six times the third angle.
I think the variables should be:
x = one angle
3x = second angle
6x = third angle
Answer by vleith(2517) About Me  (Show Source):
You can put this solution on YOUR website!
Not quite
The first angle is 3 times the second. You have the second angle as 3 times the first.
Likewise, the first angle is 6 times the third. You have the thrid angle as 6 times the first.
The angles should be x+%2C+x%2F3%2C+x%2F6
You know the sum of the angles is 180 (since this is a triangle)
180+=+x+%2B+x%2F3+%2B+x%2F6
180+=+%286x+%2B+2x+%2B+x%29%2F6
1080+=+9x
120+=+x}
So the other angles are 120/3 = 40
and 120/6 = 20
Does 120+40+20 = 180?