You can
put this solution on YOUR website!Original dimensions
Width=X
Length=X+2
New dimensions
Width=X-3
Length=X+2+4=X+6
The areas are the same the area of a rectangle is WL
X(X+2)=(X-3)(X+6)
Use the distributive property
x^2+2X=X^2-3X+6X-18
x^2+2X=x^2+3X-18
Subtract x^2 from both sides
2X=3X-18
subtract 2X from both sides
add 18 to both sides
18=X
The original dimensions of the pool is 18mX20m
The new dimensions are 15mX24m
18*20=360
15*24=360