# SOLUTION: the length of a rectangle is 3cm greater than the width.if each dimension is increased by 2cm,the areais increased by 26cm^2.find the original dimensions of the rectangle?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: the length of a rectangle is 3cm greater than the width.if each dimension is increased by 2cm,the areais increased by 26cm^2.find the original dimensions of the rectangle?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Geometry Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Geometry Word Problems Question 159750: the length of a rectangle is 3cm greater than the width.if each dimension is increased by 2cm,the areais increased by 26cm^2.find the original dimensions of the rectangle?Answer by KnightOwlTutor(293)   (Show Source): You can put this solution on YOUR website!Original dimensions X=width x+3=length New dimensions X+2=width X+5=length The area of a rectangle is W*L the change in the dimensions increased the area of the original rectangle by 26 Orignal area +26=New Area X(X+3)+26=(X+2)(X+5) Use distributive and Foil method x^2+3X+26=x^2+7X+10 Subtract x^2 from both sides 3X+26=7X+10 Subract 3X from both sides 26=4X+10 Subtract 10 from both sides 16=4X Divide both sides by 4 4=X The original dimensions of the rectangle were 4cm X 7cm The area is 28cm^2 The new dimensions are 6cm X 9cm The area is =54cm^2 54cm^2-28cm^2=26cm^2