SOLUTION: how would this be factored?
3x^3y^2-3x^2y^2+3xy^2
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Question 157749: how would this be factored?
3x^3y^2-3x^2y^2+3xy^2
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
3x^3y^2-3x^2y^2+3xy^2
3XY^2(X^2-X+1)
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