SOLUTION: Hi, I need help I solved the following problem just want to make sure it is correct: Simplify: 2x [(4x2 + 6x - 2) + (4x2 - 8x)/2x] Simplifying 2x[(4x2 + 6x + -2) + (4x2

Question 151422: Hi,
I need help I solved the following problem just want to make sure it is correct:
Simplify: 2x [(4x2 + 6x - 2) + (4x2 - 8x)/2x]
Simplifying
2x[(4x2 + 6x + -2) + (4x2 + -8x)]/2x
If it is incorrect can you tell me where.
Thank you for taken the time to help me.
Reorder the terms:
2x[(-2 + 6x + 4x2) + (4x2 + -8x)]/2x
Remove parenthesis around (-2 + 6x + 4x2)
2x[-2 + 6x + 4x2 + (4x2 + -8x)]/2x
Reorder the terms:
2x[-2 + 6x + 4x2 + (-8x + 4x2)]
Remove parenthesis around (-8x + 4x2)
2x[-2 + 6x + 4x2 + -8x + 4x2 ] /2x

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I need help I solved the following problem just want to make sure it is correct:
Simplify: 2x [(4x2 + 6x - 2) + (4x2 - 8x)/2x]
Simplifying
2x[(4x2 + 6x + -2) + (4x2 + -8x)]/2x
If it is incorrect can you tell me where.
Thank you for taken the time to help me.
Reorder the terms:
2x[(-2 + 6x + 4x2) + (4x2 + -8x)]/2x
Remove parenthesis around (-2 + 6x + 4x2)
2x[-2 + 6x + 4x2 + (4x2 + -8x)]/2x
Reorder the terms:
2x[-2 + 6x + 4x2 + (-8x + 4x2)]
Remove parenthesis around (-8x + 4x2)
2x[-2 + 6x + 4x2 + -8x + 4x2 ] /2x
----------------
Simplify: 2x [(4x2 + 6x - 2) + (4x2 - 8x)/2x]/2x
Comment It looks like you have "2x" in the numerator and "2x" in the denominator. If so, they cancel leaving you with the following:
---------------
[(4x2 + 6x - 2) + (4x2 - 8x)/2x]
= [2x(4x^2 + 6x + 2) + (4x^2-8x)]/2x
= [8x^3 + 12x^2 + 4x + 4x^2 - 8x]/2x
= [8x^3 + 16x^2 -4x] / 2x
= [2x(x^2 + 8x - 2)]/2x
= x^2 + 8x - 1
==================
Cheers,
Stan H.

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