SOLUTION: Find the verex and intercepts. Sketch the graph g(x) = x^2 + -6

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The y intercept is -6
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x^2-6=0
x^2=6
x=-sqrt(6), x=sqrt(6) the x intercepts.
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The vertex at x=sqrt(6)-sqrt(6)=0
The vertex at y=-6 special case.
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Ed

You can put this solution on YOUR website!
g(x) = x^2 + -6
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, x^2 -6).
Vertex=-6
Y Intercept=-6
X Intercepts=+-2.5

You can put this solution on YOUR website!
Edwin's solution:
Find the verex and intercepts. Sketch the graph

The vertex formula:

The graph of 



has the vertex (, ), where 

Therefore


can be written as



So we apply the vertex formula:

, , , 

so the vertex is

(, ) =

(, ) = (, )

To find the y-intercept, we substitute 





So the y-intecept is (, ), which just happens
to, in this case, be the same point as the vertex.

To find the x-intercepts, we we substitute 





 = ±
 
Since the square root of 6 is about ,

the two x intercepts are about (, ) and (, )

So we plot those two points, as well as:

vertex: (, )

and

y-intercept: (, ) [Which in this case just 
happens to be the same point as the vertex.]



Edwin