SOLUTION: I have a rather detailed problem, could I please have some help solving. Thank you. The length of a rectangle is 8ft longer than its width, which is the same dimension as the side

Question 140225: I have a rather detailed problem, could I please have some help solving.
Thank you. The length of a rectangle is 8ft longer than its width, which is the same dimension as the side of a square. If the area of the rectangle is equal to 160 square feet more than the area of the square, what are the length and width of the rectangle?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 8ft longer than its width, which is the same dimension as the side of a square. If the area of the rectangle is equal to 160 square feet more than the area of the square, what are the length and width of the rectangle?
:
Let x = width of the rectangle and the length of the side of the square
Then
(x+8) = length of the rectangle
:
Rectangle area - square area = 160 sq/ft
x(x+8) - x^2 = 160
:
x^2 + 8x - x^2 = 160
:
8x = 160
x =
x = 20 ft is the width, that makes the length 28 ft
;
:
Check solution by finding the areas
28 * 20 = 560
20 * 20 = 400
-------------
difference160; confirms our solution
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