SOLUTION: The length of a rectangle is 1 ft. more than twice the width. The area is 55 sq. ft. Find the length and width?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The length of a rectangle is 1 ft. more than twice the width. The area is 55 sq. ft. Find the length and width?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 139391:
The length of a rectangle is 1 ft. more than twice the width. The area is 55 sq. ft. Find the length and width?
Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
L=2W+1
W(2W+1)=55
2W^2+W-55=0
(2W+11)(W-5)=0
W-5=0
W=5 IS THE WIDTH MEASUREMENT.
L=2*5+1
L=10=1
L=11 IS THE LENGTH.
PROOF
5*11=55
55=55