SOLUTION: The hypotenuse of a right triangle is 6 inches longer than the shortest side and 3 inches longer than the remaining side. Find the dimensions of the triangle.

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 Question 133099: The hypotenuse of a right triangle is 6 inches longer than the shortest side and 3 inches longer than the remaining side. Find the dimensions of the triangle.Found 2 solutions by checkley71, vleith:Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!X^2+(X+3)^2=(X+6)^2 X^2+X^2+6X+9=X^2+12X+36 X^2-6X-27=0 (X-9)(X+3)=0 X-9=0 X=9 ANSWER FOR THE SHORTEST SIDE. 9+3=12 FOR THE LONGER SIDE 9+6=15 FOR THE HYPOTENUSE. PROOF: 9^2+12^2=15^2 81+144=225 225=225 Answer by vleith(2825)   (Show Source): You can put this solution on YOUR website!Let the shortest side = s. Then the hypotenuse is (s+6) and the other side is (s+6)-3 = (s+3) Using the Pythagorean theorem, So: collecting terms yields: Thus s = 9 (since it can't be a length of -3) Then the other 2 kegs are (s+3) = 12 and (s+6) = 15 Check your answer. Is 9^2 + 12^2 = 15^2? yes it is!