# SOLUTION: The lentgh of a rectangle is 2in. more than than twice its width . If the perimeter of the rectangle is 34 in.,find the dimensions of type rectangle.

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The lentgh of a rectangle is 2in. more than than twice its width . If the perimeter of the rectangle is 34 in.,find the dimensions of type rectangle.      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Geometry Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Geometry Word Problems Question 123717: The lentgh of a rectangle is 2in. more than than twice its width . If the perimeter of the rectangle is 34 in.,find the dimensions of type rectangle.Answer by nadinadan(32)   (Show Source): You can put this solution on YOUR website!First let's say L=length and W=width of the rectangle. The problem has to be changed into mathematical operations. So it says that L=2W+2 length is 2plus double the width. And the perimeter is 34. The perimeter of the rectangle is 2L+2W=34 so we have 2 equations: 2L+2W=34 L=2W+2 we will replace the second equation into the first one. 2(2W+2)+2W=34 so 4W+4+2W=34 so 6W=34-4 so 6W=30 so W=5 Now we can find what L is L=2W+2=2*5+2=12 so L=12 We can verify ourselves: P=2L+2W=24+10=34 YEAP, we are right. Let me know if you need more help: nadinadan@hotmail.com