SOLUTION: A stained-glass window is being designed in the shape of a rectangle surmounted by a semicircle, as shown in the figure. The width of the window is to be 3 feet, but the height h

Question 121582This question is from textbook algebra and trigonometry with analiytic geometry
: A stained-glass window is being designed in the shape of a rectangle surmounted by a semicircle, as shown in the figure. The width of the window is to be 3 feet, but the height h is yet to be determined. If 23 ft 2 of glass is to be used, find the height h.
Please round the answer to the nearest hundredth.
Enter your answer as a number without the units. This question is from textbook algebra and trigonometry with analiytic geometry

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE AREA OF THE SEMICIRCLE IS:
PIR^2/2=3.14*1.5^2/2=3.14*2.25/2=7.065/2=3.53 FT^2
23-3.53=19.47 FT^2
SEEING AS THE WIDTH OF THE WINDOW IS 3 THEN:
19.47/3=6.49 FEET IS THE HEIGHT OF THE RECTANGULAR WINDOW.
RELATED QUESTIONS
A stained - glass window is being designed in the shape of a rectangle surmounted by a... (answered by solver91311)