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If a circle of radius 2 is made to roll along the x-axis, what is an equation for the path of the center of the circle?
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Then the center of the circle remains at the constant height over the x-axis,
so the equation of the path of the center is
y = 2,
where "2" is the radius of the circle.
Solved, answered and explained.
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Comment from student: It makes sense that the height of the circle does not change
as it is rolling on the x-axis. Radius r = height of the circle.
My response: I noticed, that after getting every my solution, you try to re-tell it in your own words -
and every time your wording is incorrect, distorting the meaning of my words.
In Math, there is NO such conception " the height of the circle ".
So, regarding this problem and my solution, it is nonsensical to use these words.
In this problem, "r" is the height of the center of the circle over x-axis.
Math is not chewing gum in your mouth.
It assumes using proper terms and conceptions that are strictly defined,
every time and in every statement/sentence.
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Hello, personally for you, I make TWO KINDS of work at this forum.
First, I solve problems for you per your request, showing you the path
on how to do it.
Second, I teach you to speak Math properly.
Therefore, you should not take it as an offence from my side.
It is the same teaching, but of the other kind.
Math has several beauties:
- one beauty is its ideas;
- the other beauty is its technique,
- and the third beauty is its language.
All these components are important and each should be perfect.