SOLUTION: finding the x-intercepts of parabola: y= -x^2+6x-1 please help a. write the equation for the axis of symmetry. b. use the equation to create a table of values for

Question 119926: finding the x-intercepts of parabola:
y= -x^2+6x-1 please help
a. write the equation for the axis of symmetry.
b. use the equation to create a table of values for the quadratic equation finding values of both sides of the axis of symmetry.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
y= -x^2+6x-1 please help
:
a. write the equation for the axis of symmetry.
The axis of symmetry equation: x =
In the above equation a=-1: b=6, so we have:
x = = +3
The axis of symmetry is at x=3
:
b. use the equation to create a table of values for the quadratic equation finding values of both sides of the axis of symmetry.
:
Substitute each value for x in the equation and find y.
You table should look like this:
x | y
-------
-1|-8
0|-1
+1|+4
+2|+7
+3|+8; axis of symmetry, max value
+4|+7
+5|+4
+6|-1
:
Note the that x intercepts (where it crosses 0)
between x=0 and x=+1. And x=+5, and x=+6
:
Plot these values, a graph of this:

:
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