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The length of a rectangle is 6 cm. greater than its width. If the width is 2 cm less and its
length is 3 cm. greater, the area would be the same as before. Find the dimensions of the
rectangle.
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x = the width
(x+6) = the length.
Write equation as you read the problem
x*(x+6) = (x-2)*((x+6)+3).
Simplify and find x
x*(x+6) = (x-2)*(x+9)
x^2 + 6x = x^2 - 2x + 9x - 18
x^2 + 6x = x^2 + 7x - 18
6x = 7x - 18
18 = 7x - 6x
x = 18
ANSWER. The dimensions of the rectangle are 18 cm and 24 cm.
Solved.