SOLUTION: A triangular parking lot has two sides that are of the same length and the third side is 10m longer. If the perimeter is 73m, find the lengths of the sides.

Question 1196555: A triangular parking lot has two sides that are of the same length and the third side is 10m longer. If the perimeter is 73m, find the lengths of the sides.
Found 3 solutions by math_tutor2020, greenestamps, MathLover1:
Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

Answer: The three sides are 21 m, 21 m, 31 m

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Explanation:

x = length of each of the two congruent sides
x+10 = length of the third longer side

The three sides add up to the perimeter 73 meters
side1+side2+side3 = perimeter
(x)+(x)+(x+10) = 73
3x+10 = 73
3x = 73-10
3x = 63
x = 63/3
x = 21 meters is the length of the two congruent sides
x+10 = 21+10 = 31 meters is the longer side

Check:
21+21+31 = 73
The answers are confirmed.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

1st side: x
2nd side: x
3rd side: x+10

The perimeter is 73m:

x+x+x+10 = 73
3x+10 = 73
3x = 63
x = 63/3 = 21

The three side lengths are
x = 21
x = 21
x+10 = 31

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

let two sides that are of the same length be and =>....eq.1
the third side is longer =>......eq.2

if the perimeter is , we have
.....substitute and

then and
the lengths of the sides are: , ,

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