SOLUTION: A rectangluar swimming pool is 16 ft by 40ft. A tarp to go over the pool also covers a strip of equal width surrounding the pool. If the area of the tarp is 1100 ft, how wide is t

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Question 119122: A rectangluar swimming pool is 16 ft by 40ft. A tarp to go over the pool also covers a strip of equal width surrounding the pool. If the area of the tarp is 1100 ft, how wide is the covered strip around the pool, round to the nearest tenth of a foot.
Found 2 solutions by checkley71, edjones:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
THE TARP HAS THE FOLLOWING DIMENTIOS:
(16+2X)(40+2X)=1100 WHERE X=THE WIDTH OF THE STRIP.
640+80x+32x+4x^2=1100
4x^2+112x+640-1100=0
4x^2+112x-460=0
4(x^2+28x-115)=0
using the quadratic equation we get
x=(-28+-sqrt[28^2-4*1*-115])/2*1
x=(-28+-sqrt[784+460])/2
x=(-28+-sqrt1244)/2
x=(-28+-35.27)/2
x=(-28+35.27)/2
x=7.27/2
x=3.64 answer for the width of the strip.

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
Let x the width of the covered strip around the pool.
(x+16)*(x+40)=1100
x^2+56x+640=1100
x^2+56-460=0
The width of the strip is 7.3 ft (see below)
.
Ed
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=4976 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7.27038417709679, -63.2703841770968. Here's your graph:



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