SOLUTION: If the height of a right circular cone is decreased by 8 percent by what percent must the radius of the base be decreased so that the volume of the cone is decreased by 15 percent?
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Question 1183328: If the height of a right circular cone is decreased by 8 percent by what percent must the radius of the base be decreased so that the volume of the cone is decreased by 15 percent?
Found 2 solutions by josgarithmetic, ankor@dixie-net.com:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If the height of a right circular cone is decreased by 8 percent by what percent must the radius of the base be decreased so that the volume of the cone is decreased by 15 percent?
:
8% reduction = .92h
15% reduction = .85v
let a = reduced amt multiplier time the radius
= .85()
multiply both sides by 3
= .85()
divide both side by pi*r^2*h
a =
a = .9612 times the radius, therefore
Radius has to be reduced by 3.88%
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