SOLUTION: The sides of a triangle are 70cm, 80cm, and 90 cm. Compute the length of the altitude to the 80-cm side.

Question 1180833: The sides of a triangle are 70cm, 80cm, and 90 cm. Compute the length of the altitude to the 80-cm side.
Found 4 solutions by mananth, ikleyn, MathTherapy, josgarithmetic:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
sides of a triangle are 70cm, 80cm, and 90 cm.
herons formula

s= 1/2 perimeter = (70+80+90)/2 =120
a ,b , c are the sides of triangle

Area = 2683.28
Area = 1/2 base * height
2683.28= 80 *height
height = 33.54 cm^2

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

            The numbers in the solution by @mananth are incorrect.

            So I came to bring the correct solution/answer.

sides of a triangle are 70cm, 80cm, and 90 cm. Use the Heron's formula area = s= 1/2 perimeter = (70+80+90)/2 = 120 cm a, b, c are the sides of triangle area = cm^2 Area = 2683.28 cm^2 Area = 1/2 base * height 2683.28= (1/2)*80*height height = 67.08 cm. the CORRECT ANSWER

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The sides of a triangle are 70cm, 80cm, and 90 cm. Compute the length of the altitude to the 80-cm side.

That's WRONG. The height is NOT 33.54 cm. Furthermore, length is NOT denoted by square units!
Therefore, we have: ~~height = 33.54 cm^2~~.
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The altitude forms two right triangles.

The 80 cm base is in parts x and 80-x.
One of the right triangles is sides y, 70, and 80-x; y for the altitude.

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