SOLUTION: Find the equation of a parabola with axis parallel to the y-axis and passing through
(1/2, -5/2), (3/2,-9/4) and (-7/2, 3/2).
Algebra.Com
Question 1167091: Find the equation of a parabola with axis parallel to the y-axis and passing through
(1/2, -5/2), (3/2,-9/4) and (-7/2, 3/2).
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
A parabola with an axis of symmetry parallel or coincident with the 
-axis can be modeled by:
\ =\ ax^2\ +\ bx\ +\ c)
If the three given points are elements of the set of ordered pairs defined by the above function, then the following set of three linear equations in the variables a, b, and c must hold:
a\ +\ \(\frac{1}{2}\)b\ +\ c\ =\ -\frac{5}{2})
a\ +\ \(\frac{3}{2}\)b\ +\ c\ =\ -\frac{9}{4})
a\ -\ \(\frac{7}{2}\)b\ +\ c\ =\ \frac{3}{2})
Solve the 3X3 system to determine the coefficients of the desired quadratic function.
John
My calculator said it, I believe it, that settles it
I > Ø
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