The difference of the dimensions of the picture is 5 - 4 = 1 inch. Since the frame is of uniform width, the difference of the outer dimensions of the frame is 1 inch, too. The area of 110 square inches of the frame and the picture together is the product of the numbers 10 and 11 with the difference 1 unit. Therefore, the outer dimensions of the frame are 10 and 11 inches. It implies that the width of the frame is= = 3 inches. ANSWER